Question

What is the domain of $g\left(x\right)=\frac{1}{(-x+8)}$

Answer 1

$g\left(x\right)=\frac{1}{-x+8}$

domain of g(x) in $(R-8)$

$R\to realnumbers$

when $x=8$

$g\left(x\right)=\frac{1}{-8+8}$

$=\frac{1}{0}$

which is not defined

so, Domain of $g\left(x\right)=(-\infty ,8)\cup (8,+\infty )$