Question

What is the domain of $h\left(x\right)=\frac{(x-6)}{(2x-8)}$

Answer 1

$h\left(x\right)=\frac{(x-6)}{(2x-8)}$

when $x=4$

$h\left(x\right)=\frac{(4-6)}{(2\times 4-8)}$

$h\left(x\right)=\frac{-2}{8-8}$

$h\left(x\right)=\frac{-2}{0}$

which is not defined .

Domain of $h\left(x\right)=R-4,R$ is the set of all real numbers.

Domain of $h\left(x\right)=(-\infty ,4)\cup (4,\infty )$