Question

What is the electrochemical equivalent of Ag (in gram/coulomb)? (Ag = 108; F = Faraday)

• A. 108F
• B. $\frac{108}{F}$
• C. $\frac{F}{108}$
• D. $\frac{1}{108F}$

Answer 1

The correct option is B $\frac{108}{F}$

For silver,
$\text{Molecular weight}=\text{electro chemical equivalent}\times F$

$\therefore \text{Electro chemical equivalent}=\frac{108}{F}$

Hence, option B is correct.