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Standard XII

Chemistry

Electrode Potential

What is the e...

Question

What is the electrode potential in (in V) of the following electrode at
$25^{o} C > N i^{2 +} (0.1 M) | N i (s)$
(standard reaction potential of $N i^{2 +} / N i$ is $- 0.25$ V).

- 0.28

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- 0.34

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- 0.82

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- 0.22

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Solution

The correct option is B $- 0.28$ V
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{2} log \frac{1}{[{N i}^{2 +}]}$
$= - 0.25 - \frac{0.0591}{2} log (\frac{1}{0.1})$
$= - 0.2795 V$
$\approx - 0.28 V$

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Similar questions

N i | N i^{2 +} | | C u^{2 +} | C u

The standard EMF of the above cell is 0.59 V. The standard electrode potential (reduction potential) of the copper electrode is 0.34 V. Calculate the standard electrode potential of nickel electrode.

The standard oxidation potential of $N i | N i^{2 +}$ electrode = 0.236 V. If this is combined with a hydrogen electrode in acid solution, at what pH of the solution will the measured emf be zero at 25 ºC. Assume $[N i^{2 +}]$ = 1M.

Q. A solution containing equimolar amounts of

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Standard reduction potential (V) -0.236
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What is the electrode potential in (in V) of the following electrode at 25oC>Ni2+(0.1M)|Ni(s)(standard reaction potential of Ni2+/Ni is −0.25V).

The correct option is B −0.28VEcell=E0cell−0.05912log1[Ni2+] =−0.25−0.05912log(10.1) =−0.2795V ≈−0.28V

What is the electrode potential in (in V) of the following electrode at
$25^{o} C > N i^{2 +} (0.1 M) | N i (s)$
(standard reaction potential of $N i^{2 +} / N i$ is $- 0.25$ V).

The correct option is B $- 0.28$ V
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{2} log \frac{1}{[{N i}^{2 +}]}$
$= - 0.25 - \frac{0.0591}{2} log (\frac{1}{0.1})$
$= - 0.2795 V$
$\approx - 0.28 V$