What is the electron configuration for the oxide ( $O^{2 -}$ ) ion?

1 s^{2} 2 s^{2} 2 p^{6}

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1 s^{2} 2 p^{6} 3 s^{2}

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1 s^{2} 2 s^{2} 2 p^{2}

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1 s^{2} 2 s^{2} 2 p^{4}

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Solution

The correct option is A $1 s^{2} 2 s^{2} 2 p^{6}$
$O^{2 -}$ has $10$ electrons. Thus its configuration is $1 s^{2} 2 s^{2} 2 p^{6}$ We can observe that this is same as configuration of $A r$ . Hence answer is option A.

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Similar questions

Q. The electronic configuration of flourine elements respectively are :

1 s^{2}

1 s^{2} 2 s^{2} 2 p^{2}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{4}

Q. Electronic configurations of four elements

A, B, C

and

D

are given below:
(A)

1 s^{2} 2 s^{2} 2 p^{6}

(B)

1 s^{2} 2 s^{2} 2 p^{4}

(C)

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

(D)

1 s^{2} 2 s^{2} 2 p^{5}

Which of the following is the correct order of increasing tendency to gain electron?

Q. What is the electronic configuration of

O^{2 -}

ion?

Electronic configuration of four elements A, B, C, and D are given below
A. $1 s^{2} 2 s^{2} 2 p^{6}$ B. $1 s^{2} 2 s^{2} 2 p^{4}$ C. $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
D. $1 s^{2} 2 s^{2} 2 p^{5}$
Whilch of the following is the correct order of increasing tendency to gain electron?
(a) A < C <B <D (b) A < B < C < D (c) D <B < C < A (d) D < A < B <C

Q. Assertion: Nitrogen has five valence electrons

Reason: The electron configuration for nitrogen is

1 s^{2} 2 s^{2} 2 p^{6}

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What is the electron configuration for the oxide (O2−) ion?

The correct option is A 1s22s22p6O2− has 10 electrons. Thus its configuration is 1s22s22p6 We can observe that this is same as configuration of Ar. Hence answer is option A.

What is the electron configuration for the oxide ( $O^{2 -}$ ) ion?

The correct option is A $1 s^{2} 2 s^{2} 2 p^{6}$
$O^{2 -}$ has $10$ electrons. Thus its configuration is $1 s^{2} 2 s^{2} 2 p^{6}$ We can observe that this is same as configuration of $A r$ . Hence answer is option A.