What is the electron configuration of $V^{2 +}$ ?

[A r] 4 s^{2} 3 d^{3}

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[A r] 4 s^{1} 3 d^{4}

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[A r] 3 d^{3}

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[A r] 4 s^{2} 3 d^{1}

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Solution

The correct option is C $[A r] 3 d^{3}$
The electrons are removed from outermost shell. Configuration of V is $[A r] 4 s^{2} 3 d^{3}$ . Hence electrons are removed from $4 s$ . Thus configuration $V^{2 +}$ is $[A r] 3 d^{3}$ .

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Similar questions

Write the electronic configurations of the following ions:
(a) $H^{-}$
(b) $N a^{+}$
(c) $O^{2 -}$
(d) $F^{-}$

(ii) What are the atomic numbers of elements whose outermost electrons are represented by
(a) 3 $s^{1}$
(b) 2 $p^{3}$ and
(c) 3 $p^{5}$ ?

Which atoms are indicated by the following configurations?
(a) [He] 2 $s^{1}$
(b) [Ne] 3 $s^{2} 3 p^{3}$
(c) [Ar] 4 $s^{2} 3 d^{1}$

_{18}^{40} Ar

\begin{matrix} S c - [A r] 3 d^{1} 4 s^{2} & C a - [A r] 4 s^{2} M g - [N e] 3 s^{2} & C o - [A r] 3 d^{7} 4 s^{2} \end{matrix}

N a^{+}

C l^{-}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{3} {4 s}^{2}

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