Question

What is the electronic configuration of an element in its first excited state which is isoelectronic with $O_2$?

• A. $\left[Ne\right]3S^{2}3p^{3}3d^1$
• B. $\left[Ne\right]3S^{2}3p^4$
• C. $\left[Ne\right]3S^{2}3p^{3}3d^2$
• D. $\left[Ne\right]3S^{1}3p^5$

Answer 1

The correct option is B $\left[Ne\right]3S^{2}3p^4$

$O_2$ no. of electron = $8\times 2=16$

${15}^{2}2s^{2}2p^{6}3s^{2}3p^4$

$\left(Ne\right)3s^{2}3p^4$

option B is correct.