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Multi-Electron Configurations and Orbital Diagrams

What is the e...

Question

What is the electronic configuration of $O^{2 -}$ ion?

1 s^{2} 2 s^{2} 2 p^{6}

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1 s^{2} 2 s^{2} 2 p^{4}

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1 s^{2} 2 s^{2} 2 p^{5}

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1 s^{2} 2 s^{2} 2 p^{3}

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Solution

The correct option is A $1 s^{2} 2 s^{2} 2 p^{6}$
$O^{2 -}$ :

The atomic number of $O = 8$ =number of electrons

Number of electrons in $O^{2 -}$ are $8 + 2 = 10$

Electronic configuration will be $1 s^{2} 2 s^{2} 2 p^{6}$

Hence, the correct option is $A$

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Similar questions

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{3}

A, B, C

D

1 s^{2} 2 s^{2} 2 p^{6}

1 s^{2} 2 s^{2} 2 p^{4}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2}

1 s^{2} 2 s^{2} 2 p^{2}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{4}

Arrange the elements with the following electronic configurations in the increasing order of electron affinity

(i) $1 s^{2} 2 s^{2} 2 p^{3}$ (ii) $1 s^{2} 2 s^{2} 2 p^{4}$ (iii) $1 s^{2} 2 s^{2} 2 p^{5}$ (iv) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}$

1 s^{2} 2 s^{1}

1 s^{1} 2 s^{2} 2 p^{3}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{6} {3 s}^{1}

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