Question

What is the elemental composition of $H_{3}P{O}_4$?

Answer 1

Molar mass of $H_{3}P{O}_4$ = 98 gm/mol

$\%$ composition $=\frac{\text{Atomic mass}}{\text{Molecular mass}}\times 100\%$

$\%H=\frac{3\times 1\cdot g\cdot mo{l}^{-1}}{98\cdot g\cdot mo{l}^{-1}}\times 100\%=3.1\%$

$\%P=\frac{31\cdot g\cdot mo{l}^{-1}}{98\cdot g\cdot mo{l}^{-1}}\times 100\%=31.6\%$

$\%O=\frac{4\times 16\cdot g\cdot mo{l}^{-1}}{98\cdot g\cdot mo{l}^{-1}}\times 100\%=65.3\%$