What is the emitter current if IB-20 - A and - -100 -

The common emitter configuration can be shown as: We know β = I_CI_B ⇒ I_C = β× I_B = 100× 20× 10^ 6 A = 2×10^ 3 A and I_E = I_B + I_C = 20× 10^ 6 + 2× 10^ 3 ...

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Byju's Answer

Standard XI

Physics

Transistor as an Amplifier

What is the e...

Question

What is the emitter current if $I_{B} = 20 μ A$ and $β = 100$ ?

2.02 m A

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2.00 m A

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1.01 m A

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120 m A

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Solution

The correct option is A $2.02 m A$
The common emitter configuration can be shown as:

We know $β = \frac{I_{C}}{I_{B}}$
$\Rightarrow I_{C} = β \times I_{B}$
$= 100 \times 20 \times 10^{- 6} A$
$= 2 \times 10^{- 3} A$
and
$I_{E} = I_{B} + I_{C}$
$= 20 \times 10^{- 6} + 2 \times 10^{- 3}$
$= 2.02 \times 10^{- 3} A$
$= 2.02 m A$

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What is the emitter current if IB=20 μA and β=100 ?

The correct option is A 2.02 mAThe common emitter configuration can be shown as: We know β=ICIB ⇒IC=β×IB =100×20×10−6 A =2×10−3A and IE=IB+IC =20×10−6+2×10−3 =2.02×10−3 A =2.02 mA

What is the emitter current if $I_{B} = 20 μ A$ and $β = 100$ ?