Question

What is the empirical formula for a compound containing $38.8\%$ carbon,$16.2\%$ hydrogen and $45.1\%$ nitrogen?

Answer 1

Let $100gm$ of compound

man of carbon $=38.8g$.

man of hydrogen $=16.2g$

man of nitrogen $=45.1g$

number of mole of carbon $=\frac{38.8}{12}=3.176$

number of mole of hydrogen $=\frac{16.2}{1}=16.2$

number of mole of nitrogen $=\frac{45.1}{14}=3.22$

$3.176:16.2:3.22$

$1:5:1$

Empirical formula $C{H}_{3}N$