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Question

What is the empirical formula of vanadium oxide, if 2.74 g of the metal oxide contains 1.53 g of metal ?
(Molar Mass of Vanadium = 52 g)

A
V2O3
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B
VO
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C
V2O5
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D
V2O7
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Solution

The correct option is C V2O5
Metal oxide =2.74 g;
wt. of vanadium =1.53 g
% of V=1.532.74×100=55.83
Thus, % of O=10055.83=44.17
No. of moles of V=55.8352=1.1
No. of moles of O=44.1716=2.76
Simplest ratio of V and O=1:2.5 or 2:5
Hence, the empirical formula =V2O5

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