What is the energy of state in a triply ionized beryllium $(B e^{+ + +})$ of the radius, which is equal to that of ground state of hydrogen?

27.2

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54.4

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13.6

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40.8

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Solution

The correct option is A $54.4$ eV
According to question $(B e)^{+ + +}$ ground state energy is 13.6 eV
and total energy given to the atom to ionise in $+ 3$ is equal to remove three electrons which is in ground state and having energy $3 \times 13.6 e V = 40.8 e V$
So energy of state in triply ionized beryllium = 13.6 eV + 40.8 eV = 54.4 eV

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What is the energy of state in a triply ionized beryllium (Be+++) of the radius, which is equal to that of ground state of hydrogen?

What is the energy of state in a triply ionized beryllium $(B e^{+ + +})$ of the radius, which is equal to that of ground state of hydrogen?