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Question

What is the energy stored in the capacitor between terminals a and b of the network shown in the figure?
(Capacitance of each capacitance C=1μF)

468194_7453918e7b084f43bf3e0eea7a44579d.png

A
12.5μJ
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B
Zero
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C
25μJ
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D
50μJ
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Solution

The correct option is A 12.5μJ
The circuit resembles wheatstone bridge with the capacitor between b and d as bridge capacitor. Hence, it can be removed (replaced by open circuit).
By symmetry, voltage on all other capacitors is same.
Let voltage across all other capacitors be VC
Then using KVL in loop 'abea', 2VC=10
VC=5 V

Energy stored in each capacitor, E=12CV2
E=12.5 μJ

497651_468194_ans_09afa6218d3c408c87d53ce2980e69c4.png

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