Question

What is the energy stored in the capacitor between terminals a and b of the network shown in the figure?

(Capacitance of each capacitance $C=1\mu F$)

• A. $12.5\mu J$
• B. Zero
• C. $25\mu J$
• D. $50\mu J$

Answer 1

The correct option is A $12.5\mu J$

The circuit resembles wheatstone bridge with the capacitor between b and d as bridge capacitor. Hence, it can be removed (replaced by open circuit).

By symmetry, voltage on all other capacitors is same.

Let voltage across all other capacitors be $V_C$

Then using KVL in loop 'abea', $2V_C=10$

$V_C=5V$

Energy stored in each capacitor, $E=\frac{1}{2}C{V}^2$

$E=12.5\mu J$