The correct option is A 19.14 J K−1
The change in entropy for the isothermal reversible process is given as :
△S=2.303nR logV2V1
where V2 is the final volume and V1 is the initial volume
Putting all the values we get :
△S=2.303×1×8.314× log10010=19.14 J K−1
Theory:
Calculation of ΔSuniverse for an Isothermal Process:
For an isothermal process dT=0
Isothermal processes can happen reversibly and irreversibly. We have to calculate the change in entropy of the system when it is moving from state A to state B.
For a reversible isothermal process change in entropy is obtained as,
Change in entropy for system is given as,
ΔSsys=ncv,mlnT2T1+nRlnV2V1
For an isothermal process T1=T2 which makes the first term in the equation for change in entropy as zero.
Thus,
ΔSsys=nRlnV2V1