What is the equation of a curve given by the parametric form x=9+6 sec θ;y= −2−4 tanθ.
^2}{36}-\frac{(y+2)^2}{16}=1\)
Given parametric equation are,
x=9+6 sec θ
y=−2−4 tan θ
Eliminating θ from these
sec2θ−tan2θ=1
i.e., (x−96)2−(y+24)2=1
(x−9)236−(y+2)216=1