What is the equation of polar of the point (1, 2) with respect to the circle $x^{2} + y^{2} + 8 x + 2 y + 1 = 0$

$5 x - 3 y - 7 = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$5 x + 3 y + 7 = 0$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$3 x + 5 y + 1 = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$3 x - 5 y - 1 = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$5 x + 3 y + 7 = 0$

equation of polar is given by,

$x + 2 y + \frac{8}{2} . (x + 1) + \frac{2}{2} . (y + 2) + 1 = 0$

$5 x + 3 y + 7 = 0$ .

Suggest Corrections

Similar questions

x^{2} + y^{2} - 3 x + 4 y - 8 = 0

(1, - 2)

x^{2} + y^{2} - 10 x - 10 y + 25 = 0

Find the equation of the circle passing the point (1, 2) and touching the line 2x + y - 1 = 0 at the point (1, -1).

x^{2} + y^{2} - 8 x - 2 y + 12 = 0

- 1

x^{2} + y^{2} + 6 y + 5 = 0

x^{2} + y^{2} + 2 x + 8 y + 5 = 0

Join BYJU'S Learning Program