What is the equation of tangent of the curve $y = x - sin x cos x, a t x = \frac{π}{2}$

Open in App

Solution

$y = x - sin x cos x$
$\frac{d y}{d x} = 1 - cos 2 x = m (s l o p e o f t a n g e n t)$
$m$ at $x = π / 2$
$m = 1 - cos 2 x$
$m = 2$
$y = 2 x + c$
for $c$ , $(π / 2, π / 2)$ $p o i n t s a t i s f i e s t h e g i v e n e q u a t i o n$
$c = - π / 2$
$y = 2 x - π / 2$

Suggest Corrections

Similar questions

y = ∣ ∣ x^{2} - | x | ∣ ∣ a t x = - 2.

y = {s i n}^{- 1} \frac{2 x}{1 + x^{2}} a t x = \sqrt{3}

y = x + sin x cos x

x = π / 2

y = x^{2} - 4 x - 5

x = - 2

y = x - sin x cos x

y = 2 {sin}^{2} 3 x

x = \frac{π}{6}

y = | x^{2} - | x | | a t x = - 2.

Join BYJU'S Learning Program