What is the equation of tangent to a conjugate hyperbola?
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Solution
Dear Student,
Equation of tangent of a conjugate hyperbola
1. In terms of slope m Y = mX ± √b^2 - a^2m^2
2. At point (X1,Y1) XX1/a^2 - YY1/b^2 = -1
3. At point θ (theta) X/a tanθ - y/b secθ = 1