Question

What is the equation of the line $x-3y=18$ in slope-intercept form?

Answer 1

Solve for the required slope intercept form:

Given equation of line is $x-3y=18$
Converting equation of line into slope-intercept form i.e. $y=mx+b$
$$\begin{gathered} \Rightarrow x-3y=18 \\ \Rightarrow -3y=18-x \\ \Rightarrow y=\frac{1}{3}x-6 \end{gathered}$$

Hence, the given equation of line in slope-intercept form is $y=\frac{1}{3}x-6$.