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Question

What is the equation of the plane containing the parallel lines
r=a+tc, r=b+pc.

A
r(ba)×c=[abc]
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B
r(ab)×c=[abc]
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C
r(ba)×c=[abc]
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D
rc×(ba)×c=[abc]
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Solution

The correct option is A r(ba)×c=[abc]
The direction vector of both the lines is c
Hence the normal to the required plane will be a vector n which perpendicular to AB and c.
Therefore the normal vector will be
r.(AB×c)=[abc]
Or
r.((ba).×c)=[abc]
Or
r.((ab)×c)=[abc]

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