Question

What is the equation to the chord of the parabola $y^2=8x$ which is bisected at the point (2, - 3) ?

Answer 1

$y^2=8x$

Equation of chord bisected at point is $T=S^{\prime }$

$y{y}_1-8\left(\frac{x+x_1}{2}\right)=y_1^2-8x_1(-3)y-4(x+2)={(-3)}^2-8\left(2\right)-3y-4x-8=-7-3y-4x-1=03y+4x+1=0$