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Question

What is the equilibrium constant for the reaction
HB(aq.)+NaA(aq.)HA(aq.)+NaB(aq.)?

A
10
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B
0.1
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C
107
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D
1011
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Solution

The correct option is D 10
As we know, at half point of equivalence point
pH=pKa and from figure it can be seen that at half point
pH=5 for HB so its pKa is 5.
Similarly pKa is 6 for HA.
For this reaction,
K=KHB/KHA=105/106=10

149540_143888_ans.jpg

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