Question

What is the equivalent '3-Addres code' for the following "triple notation"?

$\begin{array}{cccc}& \text{Operand1}& \text{Operator}& \text{Operand2}\\ \left(1\right)& a& +& b\\ \left(2\right)& a& \times & c\\ \left(3\right)& \left(2\right)& /& \left(1\right)\\ \left(4\right)& \left(1\right)& -& \left(3\right)\end{array}$

Note: Operand is left side of operator and operand2 is right side of operator

• A. x = a + b
  y = a $\times$ c
  x = y/x
  z = x - y
• B. x = a + b
  y = a $\times$ c
  x = x/y
  x = x - y
• C. x = a + b
  y = a $\times$ c
  y = y/x
  x = x - y
• D. x = a + b
  y = a $\times$ c
  z = y/x
  z = x - y

Answer 1

The correct option is C x = a + b

y = a $\times$ c
y = y/x
x = x - y
$\begin{array}{ccccc}& \text{Operand1}& \text{Operator}& \text{Operand2}& \\ \left(1\right)& a& +& b& \Rightarrow x=a+b\\ \left(2\right)& a& \times & c& \Rightarrow y=a\times c\\ \left(3\right)& \left(2\right)& /& \left(1\right)& \Rightarrow z=y/x\\ \left(4\right)& \left(1\right)& -& \left(3\right)& \Rightarrow w=x-z\end{array}$

By optimizing the 3-address code, it can be re-written as:

x = a + b
y = a$\times$ c
y = y / x
x = x - y