Question

What is the equivalent weight of a hydride of a metal if the equivalent weight of its oxide is 28 g?

• A. 21 g
• B. 20 g
• C. 42 g
• D. 40 g

Answer 1

The correct option is A 21 g

Given, equivalent weight of the metal oxide = 28 g
Since n-factor $\left(n_f\right)$ of oxygen atom is 2, the equivalent weight of O atom = $\frac{molarmass}{n_f}=\frac{16}{2}=8$
$\therefore$ equivalent weight of the metal,
= 28 - 8 = 20 g
Also, equivalent weight of H atom
= $\frac{molarmass}{n_f}=\frac{1}{1}=1$
$\therefore$ The equivalent weight of metal hydride = 20 + 1 = 21 g