Question

What is the equivalent weight of a hydride of a metal if the equivalent weight of its oxide is 31 g?

• A. 23 g
• B. 22 g
• C. 12 g
• D. 24 g

Answer 1

The correct option is D 24 g

Given, equivalent weight of the metal oxide = 31 g
Since n-factor $\left(n_f\right)$ of oxygen atom is 2, the equivalent weight of O atom = $\frac{\text{molar mass}}{n_f}=\frac{16}{2}=8$
$\therefore$ equivalent weight of the metal,
= 31 - 8 = 23 g
Also, equivalent weight of H atom
= $\frac{\text{molar mass}}{n_f}=\frac{1}{1}=1$
$\therefore$ The equivalent weight of metal hydride = 23 + 1 = 24 g