Question

What is the equivalent weight of oxide of a metal if equivalent weight of metal chloride is $58.5$?

• A. $20$
• B. $11$
• C. $12$
• D. $31$

Answer 1

Answer: (D)

$31$

$\frac{Equivalentwt.ofmetalchloride}{Equivalentwtofmetaloxide}=\frac{massofmetalchloride}{massofmetaloxide}$

now, Equivalent of metal chloride $58.5$.

$2M+\underset{35.5}{{Cl}_2}⟶\underset{58.5}{2MCl}$

$\therefore$ Atomic mass of metal $=58.5-35.5=23$

$\therefore$ So oxide is ${Na}_{2}O$

$\therefore$ The equivalent weight of ${Na}_{2}O=\frac{2\times 23+16}{2}=61$

$\therefore$ Correct answer is $31\left(D\right)$