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Archimedes' Principle

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Question

What is the expression for upward thrust on an object submerged in water

H: Height of liquid in the container
d: Density of Liquid
P: Pressure acting on the surface of water
A: area of cross-section of container
V’: Volume of object immersed in the liquid
V: volume of the container

A

Hdg

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B

P/A

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C

V'dg

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D

Vdg

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Solution

The correct option is C V'dg
Upthrust = (Volume of liquid displaced * density of liquid * acceleration due to gravity) and the volume of liquid displaced is equal to the volume of object immersed in liquid. If it is fully submerged in a liquid then the volume of liquid displaced will be equal to the volume of the object.

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