Question

what is the expression of sec θ in the given triangle?

• A. Opposite side/adjacent side = AB/BC
• B. Adjacent side/ hypotenuse = BC/AC
• C. Hypotenuse/ adjacent side= AC/BC
• D. Opposite side/ Hypotenuse= AB/AC

Answer 1

The correct option is C

Hypotenuse/ adjacent side= AC/BC

sec $\theta$ = $\frac{Hypotenuse}{Adjacentside}$

= $\frac{AC}{BC}$