Question

What is the extra widening required for a pavement of width 10.5 m on a horizontal curve of radius 100 m, if the design speed of 95 kmph and the longest wheel base length expected on road is 5 m will be :

• A. 1.375 m
• B. 1.675 m
• C. 0.825 m
• D. 0.975 m

Answer 1

The correct option is A 1.375 m

Pavement width = 10.5 m,
$\therefore n=3$

$\text{Exra widening}=\frac{n{l}^2}{2R}+\frac{V}{9.5\sqrt{R}}$

$=\frac{3\times 5^2}{2\times 100}+\frac{95}{9.5\sqrt{100}}=1.375m$