What is the factorization of $x^{2} + 7 x - 8$ ?

(x-8) (x+1)

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(x+5) (x-9)

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(x+7) (x-2)

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(x+8) (x-1)

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Solution

The correct option is D
(x+8) (x-1)

$x^{2} + 7 x - 8$

= $x^{2} + 8 x - x - 8$

= x(x+8) - (x+8)

= (x+8) (x-1)

Suggest Corrections

Similar questions

x^{2} + 7 x + 12 = 0

x^{2} + 7 x + 12

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Factorize: $x^{2} - 7 x + 12$ .

x^{2} + 7 x + 12

x^{2} + 7 x + 10

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