Question

What is the factorization of $x^2-\frac{16x}{15}-1$?

• A. (x-)(x+1)
• B. (x-)(x-)
• C. (x-5)(x-)
• D. (x-)(x+)

Answer 1

The correct option is D

(x-)(x+)

p(x) = $x^2-\frac{16x}{15}-1$

= $x^2-\frac{5x}{3}+\frac{3x}{5}-1$

= x(x-$\frac{5}{3}$) + $\frac{3}{5}$(x-$\frac{5}{3}$)

= (x-$\frac{5}{3}$)(x+$\frac{3}{5}$)