What is the final Product during the estimation of Phosphorous by Carius Method ?

M g_{2} P_{2} O_{7}

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M g_{2} P_{2} O_{5}

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M g N H_{4} P O_{4}

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M g N H_{2} P O_{4}

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Solution

The correct option is A $M g_{2} P_{2} O_{7}$
A known mass (0.2 - 0.3 g) of the organic substance is heated with fuming nitric acid in a Carius tube for about 2 hours. The phosphorus of the organic compound gets converted into phosphoric acid. The total phosphate content of the solution is reacted with magnesia mixture (mixture of a solution containing magnesium chloride, ammonium chloride and a little ammonia) to precipitate it as $M g N H_{4} P O_{4} .$ The precipitate of $M g N H_{4} P O_{4}$ is filtered, washed, dried and then ignited to give magnesium pyrophosphate $(M g_{2} P_{2} O_{7}) .$

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