What is the final product in the given reaction?
$C H_{3} C H_{2} C l K C N - -- \to X N i / H_{2} - --- \to Y$

C H_{3} C H_{2} C H_{2} N H C O C H_{3}

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C H_{3} C H_{2} C H_{2} N H_{2}

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C H_{3} C H_{2} C H_{2} C O N H C H_{3}

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C H_{3} C H_{2} C H_{2} C O N H C O C H_{3}

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Solution

The correct option is B $C H_{3} C H_{2} C H_{2} N H_{2}$
Potassium cyanide reacts with ethyl chloride to give ethyl cyanide because KCN is predominantly ionic. Hence $C N^{-}$ exists as free ions in solution. C site is more nucleophilic than N site and available to attack the ethyl chloride. Hence, the major product will be ethyl cyanide.

$N i / H_{2}$ helps in reduction of $- C N$ to $- C H_{2} N H_{2}$
$C H_{3} C H_{2} C l K C N - -- \to C H_{3} C H_{2} C N (X) N i / H_{2} - --- \to C H_{3} C H_{2} C H_{2} N H_{2} (Y)$

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