What is the final product in the given reaction?
$C H_{3} M g B r + N H_{3} Dry ether - ---- \to$ ?

C H_{3} N H_{2}

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H_{2}

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C_{2} H_{6}

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C H_{4}

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Solution

The correct option is D $C H_{4}$
Amine contains acidic hydrogen and grignard reagent acts as strong base.
Grignard reagent being basic in nature will accept $H^{+}$ from $N H_{3}$ and forms $C H_{4}$ and $H_{2} N M g B r$
General reaction:
$R M g X + N H_{3} Dry Ether - ----- \to R H + M g X (N H_{2})$
Mechanism:

For the given reaction:
$C H_{3} M g B r + N H_{3} Dry ether - ---- \to C H_{4} + H_{2} N M g B r (Grignard reagent)$
Hence correct option is d.

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