What is the following parabola's axis of symmetry?
$y = (x - 1)^{2} + 1$

x = 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

y = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x = - 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x = 1$
Given equation of parabola is $y = (x - 1)^{2} + 1$
Axis of symmetry means about that line , the graph should be symmetric
In this parabola equation , the symmetric equation is $x - 1 = 0$
$\Rightarrow x = 1$
Therefore axis of symmetry is $x = 1$
So the correct option is $A$

Suggest Corrections

Similar questions

y = x^{2} - 2 x - 3

y = 3 x^{2} + 6 x - 1

y = x^{2} + 1

y^{2} = x - 1

A

\frac{32}{π} A

\frac{{(x - 1)}^{2}}{9} + \frac{{(y + 2)}^{2}}{16} = 1

x = l o g_{a} (b c), y = l o g_{b} (c a), z = l o g_{c} (a b),

Join BYJU'S Learning Program