Given, the charge on the particles are 2× 10 −7 C and 3× 10 −7 C. The distance between the charges is 30 cm.
The electrostatic force between the charges is given by the equation,
F= 1 4π ε 0 × q 1 q 2 r 2
Substituting the values in the above equation, we get:
F=9× 10 9 N⋅ m 2 / C −2 × 2× 10 −7 C×3× 10 −7 C ( 30× 10 −2 m ) 2 =6× 10 −3 N
The electrostatic force between the charges is 6× 10 −3 N and it is repulsive in nature.
The force between two small charged spheres having charges 3 × 10-6C and 4 × 10-6C placed 40 cm apart in air is