Question

What is the formation of $3$ numbers, using three digit number $829$? (Without repeating the numbers in three digit)

• A. $298,988$ and $892$
• B. $228,928$ and $892$
• C. $298,928$ and $882$
• D. $298,928$ and $892$

Answer 1

The correct option is D $298,928$ and $892$

$829$ can be written using the general form $abc=100\times a+10\times b+c$
By changing the alphabetic orders of $a,b,c$, we get $3$ more numbers from $3$ digit number.
Here, $298,928$ and $892$ are formed from the $3$ digit number $829$.