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Perspective of looking at a solid

What is the f...

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What is the formula for \log_a^x< y ?

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y = l o g_{a} x

to be defined 'a' must be

\frac{d y}{d x}

y = l o g_{a} x + l o g_{x} a + l o g_{x} x + l o g_{a} a

y = \log_{a} x, find \frac{d y}{d x} .

Q. Which of the following is/are true for

a > 1

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

is an increasing function.

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