What is the formula for the n th term of an A.P.?

a + (n-1)d

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a + (n+1)d

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a + (3n-1)d

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2a + (n-1)d

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Solution

The correct option is A
a + (n-1)d

nth term of an AP whose first term is 'a' and the common difference is d is given by " a + (n-1)d ".

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Similar questions

The (n+1)th term from the end in the expansion of $(2 x - \frac{1}{x})^{3 n}$ is:

n

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3 n^{2} - n

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