What is the formula of the coordination complexes when a $N i^{2 +}$ ion is bound to two water molecules and two bidentate oxalate ions ?

[N i (H_{2} O)_{2} (C_{2} O_{4})_{2}]^{2 -}

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[N i (H_{2} O)_{3} (C_{2} O_{4})_{2}]^{2 -}

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[N i (H_{2} O)_{2} (C_{2} O_{4})_{2}]^{2 +}

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[N i (H_{2} O)_{2} (C_{2} O_{4})_{4}]^{2 -}

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Solution

The correct option is A $[N i (H_{2} O)_{2} (C_{2} O_{4})_{2}]^{2 -}$
When $N i^{2 +}$ ion is bound to two water molecules and two bidentate oxalate ions then the formula of the co-ordination complex is-

$[N i (H_{2} O)_{2} (C_{2} O_{4})_{2}]^{2 -}$ .
Here 2 water molecules bound to $N i$ atom and 2 ambident ligands are also bound, the overall charge is -2

Hence, option A is correct.

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What is the formula of the coordination complexes when a Ni2+ ion is bound to two water molecules and two bidentate oxalate ions ?

What is the formula of the coordination complexes when a $N i^{2 +}$ ion is bound to two water molecules and two bidentate oxalate ions ?