what is the formula used to calculate the height of a magnet levitated from a super conductor?

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Solution

$F o r m u l a u s e d t o c a l c u l a t e h e i g h t, F = \frac{B^{2} S}{2 μ_{0}} D i f f e r e n c e o f F o r c e s a t t o p a n d b o t t o m, F_{b} - F_{t} = F_{g} \frac{1}{2 μ_{0}} (B_{b}^{2} - B_{t}^{2}) = ρ g h$

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