Question

What is the fractional error in g calculated from $T=2\pi \sqrt{l/g}$?

Given fraction errors in T and l are $\pm$ x and $\pm$ y respectively.

• A. x+y
• B. x-y
• C. 2x+y
• D. 2x-y

Answer 1

The correct option is C 2x+y

From $T=2\pi \sqrt{\frac{l}{g}};g=4{\pi }^2\frac{l}{T^2}$

$\frac{\Delta g}{g}=\frac{\Delta l}{l}+\frac{2\Delta T}{T}=(y+2x)$