Question

What is the free energy change $△G$, when $1.0$ mole of water at ${100}^{o}C$ and $1$ atm pressure is converted steam at ${100}^{o}C$ and $1$ atm pressure:-

• A. +540 cal
• B. -9800 cal
• C. +9800 cal
• D. 0 cal

Answer 1

Answer: (D)

0 cal

As we know that $\Delta G$ at equilibrium is always $0$. So, here also is equilibrium ; so $\Delta G=0$