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Standard XII

Chemistry

Positive Rays and Neutrons

What is the f...

Question

What is the frequency of light emitted when an electron in a hydrogen atom jumps from 2nd orbit to 1st orbit?

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Solution

$n_{2} = 2$ to $n_{1} = 1$
$E = 13.6 Z^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$
E=hv= $13.6 \times 1 \times (1 - \frac{1}{4})$
h=planck's constant
$v \times 6.626 \times 10^{- 34} = 10.2 \times 1.6 \times 10^{- 19} v = 24.63 \times 10^{15} H z$

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What is the frequency of light emitted when an electron in a hydrogen atom jumps from 2nd orbit to 1st orbit?

n2=2 to n1=1E=13.6Z2(1n21−1n22)E=hv=13.6×1×(1−14)h=planck's constantv×6.626×10−34=10.2×1.6×10−19v=24.63×1015Hz

$n_{2} = 2$ to $n_{1} = 1$
$E = 13.6 Z^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$
E=hv= $13.6 \times 1 \times (1 - \frac{1}{4})$
h=planck's constant
$v \times 6.626 \times 10^{- 34} = 10.2 \times 1.6 \times 10^{- 19} v = 24.63 \times 10^{15} H z$