What is the function of $Z n C l_{2}$ (anhyd) in Lucas test for distinction between $1^{0}, 2^{0}$ and $3^{0}$ alcohols?

Open in App

Solution

Lucas reagent reacts with alcohols to form precipitates of alkyl halides.
$Z n C l_{2}$ is a Lewis acid due to the empty d orbitals of $Z n$ . Oxygen of $- O H$ forms coordinate bond with $Z n$ or in other words complexes with zinc.
Oxygen acquires a positive charge & $Z n$ acquires a negative charge. Thus, oxygen becomes a good leaving group and the reaction progresses in the forward reaction.

Suggest Corrections

Similar questions

Q. What is the function of anhydous

Z n C l_{2}

in Lucas test for distinction between

1^{o}, 2^{o} and 3^{o}

alcohols?

Q. The function of

Z n {C l}_{2}

in Lucas test for alcohols is:

Lucas reagent (anhyd. ZnCl₂ and conc HCl) was added to a certain alcohol, turbidity appeared immediately. What type of alcohol it is?

Lucas test of alcohols involves the following reaction $R - O H + C o n c . H C l A n h y d r o u s - ----- \to Z n C l_{2} R C l + H_{2} O$ (white turbidity) Select the incorrect statements for the lucas test

Q. Assertion :Tertiary alcohols give turbidity immediately with Lucas reagent. Reason: A mixture of conc.HI + anhydrous

Z n C l_{2}

is called Lucas reagent

Join BYJU'S Learning Program

What is the function of ZnCl2 (anhyd) in Lucas test for distinction between 10,20 and 30 alcohols?

What is the function of $Z n C l_{2}$ (anhyd) in Lucas test for distinction between $1^{0}, 2^{0}$ and $3^{0}$ alcohols?