Question

What is the geometry of $H_{2}S{O}_4$?

• A. Square bipyramidal
• B. Tetrahedral
• C. Trigonal bipyramidal
• D. Pentagonal bipyramidal

Answer 1

The correct option is B

Tetrahedral

Firstly, we will check out the geometry of $H_{2}S{O}_4$ using VSEPR Theory.

It will be square byramidal [ep = 6].

But the geometry of $H_{2}S{O}_4$ is not square bipyramical.

Guess why? [Answer will be given at the end of solution]

Now, we will apply AVSEPR Theory,

ep= $\frac{(V+L+A-C)}{2}=\frac{(6+2)}{2}$ =4 [S - 6]

[By ignoring oxygen while calculating ep]

Therefore, the geometry of $H_{2}S{O}_4$ is Tetrahedral.