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Gravitational Force

What is the g...

Question

What is the gravitational field strength at the surface of Jupiter (mass $1.9 \times 10^{27} k g$ , radius $7.1 \times 10^{7} m$ ?

25 N k g^{- 1}

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25 N k g^{- 2}

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35 N k g^{- 1}

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55 N k g^{- 2}

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Solution

The correct option is A $25 N k g^{- 1}$
Gravitational field = $K \frac{m 1}{r^{2}}$
where $K$ is universal gravitational constant $m_{1}$ is the mass $r$ is the distance.
G= $6.67 \times 10^{- 11} \frac{1.9 (10^{27})}{{(7.1 \times 10^{7})}^{2}}$

= $25 N {k g}^{- 1}$

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\times 10^{20} k g a n d t h e r a d i u s i s 1.74 \times 10^{6}

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G = 6.67 \times 10^{- 11}

N m^{2} k g^{- 2}

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