What is the greatest number of 4 digits that which divided by any of the numbers 6, 9, 12, 17 leave remainder of 1?
A
9997
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B
9793
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C
9895
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D
9487
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Solution
The correct option is B 9793 LCM of 6, 9, 12, 17 = 612
greatest number of 4 digit divisible by 612 is 9792
to get remainder 1 number should be 9792+1 =9793